Answer:
The distance between the points (-3, -6) and (5, 9) is 15 units.
Step-by-step explanation:
Given the points
First, we need to find the distance between the two x-coordinates. For this, we need to count the distance from 0 to another point. Then we just add them together.
i.e.
-3 to get to 0 takes 3 units
0 to 5 takes 5 units
3+5=8 units
Just do the same for y-coordinate
From -6 to 0 takes 6 units
0 to 9 takes 9 units
6+9 = 15 units
Therefore, we get the base and height.
Now using the Pythagoras' Theorem to find the distance:
c² = 8² + 15²
c² = 289
[tex]\mathrm{For\:}x^2=f\left(a\right)\mathrm{\:the\:solutions\:are\:}x=\sqrt{f\left(a\right)},\:\:-\sqrt{f\left(a\right)}[/tex]
[tex]c=\sqrt{289},\:c=-\sqrt{289}[/tex]
[tex]c=17,\:c=-17[/tex]
As the distance can not be negative.
so
Thus, the distance between the points (-3, -6) and (5, 9) is 15 units.
