Find the magnitude of the gravitational force
on Mars, with a mass of 6.34 x 1023 kg and a
radius of 3.43 x 106
Answer in units of N.

Respuesta :

Answer:

6849.4

Step-by-step explanation:

m(r)(r) mass and radius equals N

The magnitude of the gravitational force  on Mars is 3.6N

Newton's law of gravitation states that the force is directly proportional to the product of the two masses and inversely proportional to the square of the distance between them. It is given by:

F = G(m₁m₂)/r²

where m₁ and m₂ are mass, r is the distance, G is constant = 6.67 * 10⁻11 Nm²/kg² and F is the force.

Given m₁ = m₂ = 6.34 * 10²³, F = 3.43 x 10⁶, hence:

F = 6.67 * 10⁻¹¹(6.34 * 10²³)² / ( 3.43 x 10⁶)²

F = 3.6N

Hence the magnitude of the gravitational force  on Mars is 3.6N.

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