the 8th term of the geometric sequence 8, 16, 32 is 1024
Explanation
we know that
geometric sequence 8, 16, 32
the question is
the 8th term
the answer is
first we have to find the ratio
[tex] \sf r= \frac{ U_2}{U_1} \\ \sf r= \frac{ 16}{8} \\ \sf r = 2 [/tex]
than, we have to find the 8th term
[tex] \sf U_n = ar^{n-1} \\ \sf U_8 = 8 \times 2^{8-1} \\ \sf U_8 = 8 \times 2^7 \\ \sf U_8 = 8 \times 128 \\ \bold {\sf U_8 = 1024} [/tex]
Learn more
About geometric pattern
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Answer details
grade: 7th
subject: mathematics
chapter: sequence
keywords: geometric sequence
