Hi there!
[tex]\large\boxed{x = \frac{3}{4}, y = \frac{9}{4}}}[/tex]
8x + 4y = 15
x + y = 3
Use the second equation to solve for a particular variable since it is easier to isolate. We can begin by solving for y:
x + y = 3
Subtract y from both sides:
x = -y + 3
Substitute in this expression for x into the other equation:
8(-y + 3) + 4y = 15
Distribute and simplify:
-8y + 24 + 4y = 15
-4y + 24 = 15
-4y = -9
y = 9/4
Substitute in this value of y to solve for x:
8x + 4(9/4) = 15
8x + 9 = 15
8x = 6
x = 6/8 = 3/4
The values respectively are:
x = 3/4, y = 9/4
