A dolphin jumps from the water with an initial velocity of 44 feet per second at an elevation angle of 60°. Which parametric equations model the dolphin’s path through the air?

x(t) = sin(60o)t + 44 and y(t) = –16t2 + cos(60o)t + 44
x(t) = cos(60o)t + 44 and y(t) = –16t2 + sin(60o)t + 44
x(t) = 44sin(60o)t and y(t) = –16t2 + 44cos(60o)t
x(t) = 44cos(60o)t and y(t) = –16t2 + 44sin(60o)t

Respuesta :

D.   x(t) = 44cos(60o)t and y(t) = –16t2 + 44sin(60o)t

For your question: A dolphin jumps from the water with an initial velocity of 44 feet per second at an elevation angle of 60°. Which parametric equations model the dolphin’s path through the air?

After doing the math in my notebook, I got the answer D.

Please let me know if you have any other questions down below.

The parametric equations model the dolphin’s path through the air will be x(t) = 44cos(60o)t and y(t) = –16t2 + 44sin(60o)t.

What is the standard equation of a parabola?

The standard equation of a parabola is given by:

y = (x-h)² + k

Where (h, k) is the vertex of the parabola.

A dolphin jumps from the water with an initial velocity of 44 feet per second at an elevation angle of 60°.

Therefore, the amplitude of the equation must be 44 feet and the phase angle will be 60 degrees.

Therefore, The parametric equations model the dolphin’s path through the air will be x(t) = 44cos(60o)t and y(t) = –16t2 + 44sin(60o)t.

Learn more about parabolas here-

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