Question

A 0.200-kg cube of ice (frozen water) is floating in glycerine. The gylcerine is in a tall cylinder that has inside radius 3.40 cm . The level of the glycerine is well below the top of the cylinder. Part AIf the ice completely melts, by what distance does the height of liquid in the cylinder change?Express your answer with the appropriate units. d =

Answer 1

First, calculate the volume of 0.200 kg of water: d = m/V
d = 1 g/cm^3
m= 200 g

V = m/d = 200 g / 1 g /cm^3 = 200 cm^3

Now, calculate the height of this volumen inside a cylinder with inside radius 3.40 cm

V = π (r^2)*heigth => height = V / [3.1416* (3.40cm)^2]=200 cm^3 / 36.32 cm^2 = 5.51 cm

Answer: 5.51 cm