Answer:
C
Step-by-step explanation:
We have the system of equations:
[tex]\left\{\begin{array}{ll}2x-5y=-5 \\ x+2y=11\end{array}[/tex]
And an ordered pair (10, 5).
In order for an ordered pair to satisfy any system of equations, the ordered pair must satisfy both equations.
So, we can eliminate choices A and B. Satisfying only one of the equations does not satisfy the system of equations.
Let’s test the ordered pair. Substituting the values into the first equation, we acquire:
[tex]2(10)-5(5)\stackrel{?}{=}-5[/tex]
Evaluate:
[tex]20-25\stackrel{?}{=}-5[/tex]
Evaluate:
[tex]-5\stackrel{\checkmark}{=} -5[/tex]
So, our ordered pair satisfies the first equation.
Now, we must test it for the second equation. Substituting gives:
[tex](10)+2(5)\stackrel{?}{=} 11[/tex]
Evaluate:
[tex]20\neq 11[/tex]
So, the ordered pair does not satisfy the second equation.
Since it does not satisfy both of the equations, the ordered pair is not a solution to the system because it makes at least one of the equations false.
Therefore, our answer is C.