Question

What is the slope of a line that is perpendicular to the line whose equation is 8y−5x=11?

Ill give someone brainlist

Answer 1

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Answer:

  -8/5

Step-by-step explanation:

When you solve for y, the slope of the line is the x-coefficient. For the given line, that is ...

  8y = 5x +11 . . . . . add 5x

  y = 5/8x +11/8 . . . . divide by 8

The given line has a slope of 5/8. The perpendicular line will have a slope that is the opposite of the reciprocal of this:

  -1/(5/8) = -8/5 . . . . slope of perpendicular line

Answer 2

Answer:

The slope of the perpendicular line will be -8/5, or -1.6

Step-by-step explanation:

First we need to rearrange the equation to show the slope, putting in the format y = sx + c:

$8y - 5x = 11\\8y = 5x + 11\\y = \frac{5}{8}x + \frac{11}{8}$

So the given line has a slope of 5/8.

A line perpendicular to that will have a negative reciprocal of that slope, so it's slope will be -8/5.