Question

PLEASE HELPP!!!




The dimensions of triangle B are twice the dimensions of triangle A. The area of triangle A is 28 cm2.


What is the area of triangle B?

A.

112 cm2

B.

18 cm2

C.

12 cm2

D.

27 cm2

Answer 1

Answer:

Area of triangle B is 112 cm²

Option A is correct option.

Step-by-step explanation:

The dimensions of triangle B are twice the dimensions of triangle A.

Area of triangle A = 28 cm²

We need to find area of triangle B

We know that if base = b and height = h for triangle A

The area of triangle A will be: $Area_A=\frac{1}{2}\times b \times h$

The dimensions for triangle B will be:

$h_B = 2 h_A\\b_B = 2 b_A$

Putting in formula we get:

$Area_B=\frac{1}{2}\times b\times h \\Area_B=\frac{1}{2}\times (2b)\times 2(h)\\Area_B=4( \frac{1}{2}\times b\times h)\\Area_B=4(Area_A)$

SO, we get $Area_B=4(Area_A)$

We have Area_A = 28 cm²

Area of triangle B Area _B is:

$Area_B=4(28)\\Area_B=112\:cm^2$

So, Area of triangle B is 112 cm²

Option A is correct option.