Answer:
Average atomic mass = 57.79 amu
Percent contribution of Ni-60 = 26.45%
Percent contribution of Ni-5 = 73.55%
Explanation:
Given data:
Number of atoms of Ni-60 = 32
Number of atoms of Ni-57 = 89
Percent distribution of both isotopes = ?
Average atomic mass of sample = ?
Solution:
Percent contribution:
Total number of atoms = Ni-60 + Ni-57
Total number of atoms = 32 +89 = 121
Percent contribution of Ni-60 = 32/121×100
= 26.45%
Percent contribution of Ni-57 = 89/121×100
= 73.55%
Average atomic mass:
Average atomic mass = (abundance of 1st isotope × its atomic mass) +(abundance of 2nd isotope × its atomic mass) / 100
Average atomic mass = (26.45×60)+(73.55×57) /100
Average atomic mass = 1587 + 4192.35 / 100
Average atomic mass = 5779.35 / 100
Average atomic mass = 57.79 amu.