Question

What are the solutions of the equation (x+2)^2-2(x+2)-15=0

Answer 1

Answer:

The solutions to this are x = -5, and x = 3.

Step-by-step explanation:

This can be solved by rearranging the equation into a proper quadratic format, and factoring it:

$(x + 2)^2 - 2 (x + 2) - 15 = 0\\x^2 + 4x + 4 - 2x - 4 - 15 = 0\\x^2 + 2x - 15 = 0\\(x + 5)(x - 3) = 0$

This tells us that the x can be equal to  -5 or 3.