Answer:
[tex]126.5\ ft[/tex]
Step-by-step explanation:
[tex]We\ are\ given\ that,\\Sides\ of\ the\ formed\ square=90\ ft\\As\ we\ know\ that,\\s^2+s^2=d^2[Pythagoras\ Property]\\2s^2=d^2\\Hence,\\\sqrt{2s^2} = \sqrt{d^2} \\\sqrt{2}s=d\\Hence,\\As\ the\ distance\ between\ Base\ 1\ and\ 3\ is\ the\ diagonal.\\Hence,\\The\ distance\ between\ Base\ 1\ and\ 3=\sqrt{2}*Side\\ The\ distance\ between\ Base\ 1\ and\ 3=\sqrt{2}*90\\Hence,\\[/tex]
[tex]The\ distance\ between\ Base\ 1\ and\ 3=\sqrt{2}*\sqrt{8100} \\The\ distance\ between\ Base\ 1\ and\ 3=\sqrt{2*8100}\\The\ distance\ between\ Base\ 1\ and\ 3=\sqrt{16200}\\Hence,\\The\ distance\ between\ Base\ 1\ and\ 3=126.49\ ft\ or\ 126.5\ ft[/tex]
