50 POINTS!!! PLZ HELP!!! Mark has a BMR of 2,200 calories. He is not feeling well, so he checked his temperature. Mark has a fever of 99.6ºF. His BMR now would be
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When the internal body temperature increases by 33°F, there is an increases in BMR (Body metabolic rate) by 7%.
Mark has a BMR of 2,200 calories
Mark has a fever of 99.6ºF
increase in body temperature = 99.6/33 = 3.02
now percentage increase in BMR = 3.02 x 7 = 21.14% = 0.2114
increase in BMR = 2200 x 0.2114 = 465.08
His BMR now would be = 2200 + 465.08 = 2665.08

Answer:

When the internal body temperature increases by 33°F, there is an increases in BMR (Body metabolic rate) by 7%.

Mark has a BMR of 2,200 calories

Mark has a fever of 99.6ºF

increase in body temperature = 99.6/33 = 3.02

now percentage increase in BMR = 3.02 x 7 = 21.14% = 0.2114

increase in BMR = 2200 x 0.2114 = 465.08

His BMR now would be = 2200 + 465.08 = 2665.08

Explanation:

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