Respuesta :
Answer:
18.032m/s, 16.59m
Explanation:
Used to find the distance traveled
y=1/2gt^2, where y= vertical distance, g=acceleration due to gravity, and t=time
y=1/2*9.8*1.84^2
y=16.59m distance
Used to solve the final velocity before hitting the ground
vf=vo+at where vf=final velocity, vo=initial velocity, a=acceleeration, t=time
vf=0+9.8*1.84
vf=18.032m/s
Answer:
18.032m/s, 16.59m
Explanation:
Hope this helps!
Have a great day! :)