A horizontal force of 350 NN is exerted on a 2.0-kgkg ball as it rotates (at arm's length) uniformly in a horizontal circle of radius 0.90 mm. Part A Calculate the speed of the ball. Express your answer to two significant figures and include the appropriate units.

Respuesta :

Answer:

The value is  [tex]v = 12.6 \ m/s[/tex]

Explanation:

From the question we are told that

    The horizontal force is  [tex]F_h = 350\ N[/tex]

    The mass of the ball is  [tex]m = 2.0 \ kg[/tex]

     The radius is     [tex]r = 0.90 \ m[/tex]

     

Generally the speed of the ball is mathematically evaluated from  the formula for  centripetal force as

         [tex]F_ h = \frac{mv^2}{ r }[/tex]

=>       [tex]v = \sqrt{\frac{ F_h * r }{ m }}[/tex]

=>       [tex]v = \sqrt{\frac{ 350 * 0.9 }{ 2 }}[/tex]

=>      [tex]v = 12.6 \ m/s[/tex]

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