Question

Suppose a clay model of a koala bear has a mass of 0.235 kg and slides on ice at a speed of 0.720 m/s. It runs into another clay model, which is initially motionless and has a mass of 0.305 kg. Both being soft clay, they naturally stick together. What is their final velocity (in m/s)

Answer 1

Answer:

The value is  $v = 0.3133 \ m/s$

Explanation:

From the question we are told that

     The mass  of the first  model is  $m_1 = 0.235 \ kg$

      The sliding speed is $u_1 = 0.720 \ m/s$  

       The mass of the second model is  $m_2 = 0.305 \ kg$

       

Generally from the law of momentum conservation w have that

                $m_1 * u_1 + m_2 * m_2 * u_2 = (m_1 + m_2 ) v$

Here $u_2$ is the velocity of the second model and given that it is  motionless at it initial state the value will be  $u_2 = 0 \ m/ s$

 So  

                $0.235 * 0.720 + 0.305 * 0 = (0.235 + 0.305 ) v$

=>              $v = 0.3133 \ m/s$