What is the change in internal energy (deltaE ) of a system when it loses 76.0 J of heat while the surroundings perform 29.0 J of work

Respuesta :

Answer:

-47 J

Explanation:

Given that,

Heat loss = -76 J (negative for loss)

Work done by the surroundings = -29 J

We need to find the change in internal energy of a system.

The first law of thermodynamics is given by :

[tex]\Delta U=Q-W[/tex]

W is work done by the system

Putting all the values,

[tex]\Delta U=(-76)-(-29)\\\\=-47\ J[/tex]

Hence, the change in internal energy is -47 J.

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