Question

At what angle in degrees is the first-order maximum for 460-nm wavelength blue light falling on double slits separated by 0.0500 mm?

Answer 1

Answer:

The angle is $\theta = 0.52^o$

Explanation:

From the question we are told that

    The number of order is  n =  1

     The wavelength is   $\lambda = 460 \ nm = 460 *10^{- 9} \ m$

     The separation between the slit is  $d = 0.0500 \ mm = 5 *10^{-5} \ m$

Generally the condition for constructive interference is  

         $d sin \theta = n * \lambda$

=>     $\theta = sin^{-1}[\frac{n * \lambda }{ d} ]$

=>    $\theta = sin^{-1}[\frac{1 * 450 *10^{-9}}{ 5*10^{-5}} ]$

=>    $\theta = sin^{-1}[0.009 ]$

=>    $\theta = 0.52^o$