What is the relationship among mL BCD, M L A, and m L B in the figure below?
B
75
40°
A.
40 ° + 75° = 180° - m 2 BCD
В.
40° + 75° = m 2 BCD
C 40° - 75º = m 2 BCD
D
40° - 75°+ m BCD = 180°
![What is the relationship among mL BCD M L A and m L B in the figure below B 75 40 A 40 75 180 m 2 BCD В 40 75 m 2 BCD C 40 75º m 2 BCD D 40 75 m BCD 180 class=](https://us-static.z-dn.net/files/de3/a35ea37d7826c3c37c1e5dc8d8f72956.png)