Answer:
The magnetic field strength needed is 1.5 T.
Explanation:
Given;
number of turns, N = 200 turn
length of the each side of the square loop, L = 20 cm = 0.2 m
maximum torque created, τ = 300 N-m
current through the loop, I = 25 A
The maximum torque created in the is the loop is given by;
τ = NIBA
Where;
B is the magnetic field strength, which is calculated as;
[tex]B = \frac{\tau}{NIA}\\\\B = \frac{300}{200 \times \ \ 25 \ \times\ \ (0.2)^2}\\\\B = 1.5 \ T \\[/tex]
Therefore, the magnetic field strength needed is 1.5 T.
Induced magnetic field strength is defined as the number of magnetic flux lines per unit area.The magnetic field strength will be 1.5 T.
Induced magnetic field strength is defined as the number of magnetic flux lines per unit area that pass perpendicular to a particular line direction. B stands for it.
The given data in the problem is
(I) is the current=25.0A
B is the induced magnetic field=?
τ is the Torque= 300 N-M
n is the number of loop=200
L is length of the each side of the square loop = 20 cm = 0.2 m
The maximum torque created in the loop will be
[tex]\rm \tau =NIBA\\\\ \rm B=\frac{\tau}{IBA} \\\\\rm B=\frac{600}{200\times25\times(0.2)^2}\\\\\rm B=1.5T\\[/tex]
Hence the magnetic field strength will be 1.5 T.
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