Question

Adrian Beltre hit 48 home runs during the 2004 Major League Baseball season, but only hit 19 home runs in the 2005 season. By what percent did Beltre's home run production decrease from 2004 to 2005?

Answer 1

Answer:

60.42%

Step-by-step explanation:

Number of home runs hit by Adrian Beltre in 2004 = 48

Number of home runs hit by Adrian Beltre in 2005 = 19

To find:

Percentage decrease in home run production from 2004 to 2005.

Solution:

To find the percentage decrease, first of all we need to find the decrease in the number of home runs and then we will divide with the number of home runs in 2004 and then finally will multiply the result with 100 to get the percentage decrease.

Decrease in the number of home runs = Number of home runs in 2004 - Number of home runs in 2005 = 48 - 19 = 29

$\text{Percentage of decrease in Home runs} = \dfrac{\text{Decrease in home runs}}{\text{Number of home runs in 2004}}\times 100\\\Rightarrow \text{Percentage of decrease in Home runs} = \dfrac{29}{48}\times 100 \approx \bold{60.42\%}$

Therefore, by 60.42% Beltre's home run production has decreased from 2004 to 2005.

Answer 2

Percent decrease from 2004 to 2005 is 60.14%

Given that;

Number of home run hit in 2004 = 48

Number of home run hit in 2005 = 19

Find:

Percent decrease from 2004 to 2005

Computation:

Percent decrease from 2004 to 2005 = [(48 - 19) / 48]100

Percent decrease from 2004 to 2005 = [(29) / 48]100

Percent decrease from 2004 to 2005 = 60.14%

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