Question

A coffee cup calorimeter contains 153.21 g of water at 22.50 °C. A 65.454 g piece of iron is heated to 101.62 °C. The piece of iron is added to the coffee cup caloriemter and the contents reach thermal equilibrium at 25.68 °C. The specific heat capacity of iron is 0.449 Jg·K and the specific heat capacity of water is 4.184 Jg·K. How much heat, , is lost by the piece of iron?

Answer 1

Answer:

Q = 2232J

Explanation:

In the system, the energy that is lost by the iron is:

Q = S*ΔT*m

Where Q is heat, S is specific heat of iron ΔT is change in temperature and m is mass of the piece of iron.

S = 0.449J/gK

ΔT = 101.62°C - 25.68°C = 75.94°C

m = 65.454g

Q = 0.449J/gK*75.94°C*65.454g

Q = 2232J