Question

16) Avery selects two chips from a bag without looking at them. The bag has 5 green chips, 3 red chips, and 7 blue chips. What is the probability that he selects a red and then a blue chip (without replacing)? * 6 points 2/3 7/75 1/10 2/45

Answer 1

Answer:  $\dfrac{1}{10}$

Step-by-step explanation:

Given: The bag has 5 green chips, 3 red chips, and 7 blue chips.

Total chips = 5+3+7= 15

Number of ways to select a red and then a blue chip = 3 x 7 = 21

Total number of ways to select 2 chips without replacement = 15 x 14 =210

Required probability = $\dfrac{\text{favorable outcomes}}{\text{Total outcomes}}$

$=\dfrac{21}{210}=\dfrac{1}{10}$

So, the probability that he selects a red and then a blue chip (without replacing) =  $\dfrac{1}{10}$