Answer:
[tex] \huge{ \boxed{ \bold{ \sf{y = - 2x + 6}}}}[/tex]
☥ [tex] \tt{Question} : [/tex]
- Write the equation of a line in slope - intercept form that has a slope of -2 and passes through the point ( - 1 , 8 ).
☥ [tex] \tt{Step - \: by \: - \: step \: explanation}[/tex]
☪ [tex] \underline{ \underline{ \text{Given : }}}[/tex]
- Slope ( m ) = -2
- Given point = ( - 1 , 8 )
☪ [tex] \underline {\underline{ \text{To \: find}}} : [/tex]
- Equation of a line in slope - intercept form ( i.e y = mx + c )
Let the point ( -1 , 8 ) be ( x₁ , y₁ )
☪ [tex] \underline{ \underline{ \text{Solution}}} : [/tex]
[tex] \underline{ \sf{y - y1 = m(x - x1)}}[/tex]
plug the known values :
↦ [tex] \text{y - 8 = - 2 \{ x - ( - 1) \} }[/tex]
↦ [tex] \text{y - 8 = - 2(x + 1)}[/tex]
Distribute -2 through the parentheses :
↦ [tex] \text{y - 8 = - 2x - 2}[/tex]
Transpose 8 to right hand side and change it's sign
↦ [tex] \text{y = - 2x - 2 + 8}[/tex]
↦ [tex] \boxed{ \text{y = - 2x + 6}}[/tex]
And we're done !
Hope I helped!
♡ Have a wonderful day / night ツ
~TheAnimeGirl ♪
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