Question

Use the ideal gas law formula (PV = nRT R = 0.0821 L atm/mol K) to determine the volume of 1.00
mole of a gas under the following conditions:
T= 273 K P = 2.00 atm
V=_
IL
T = 546 K, P = 1.00 atm
V =
L L
T = 409.5 K P = 1.50 atm
V=L

Answer 1

Answer:

11.2 , 44.8 , 22.4

Explanation:

on edge

Answer 2

The volume with the help of the ideal gas equation for the first condition is 11.2L, the second condition is 44.8L, and for the third condition is 22.4L.

Ideal gas equation

$PV=nRT$

where P =pressure, V = volume, n = moles of gas, R = rydberg constant, and T = temperature.

Rearrange the above equation for the calculation of Volume as follows,

$V=\frac{nRT}{P}$

We can calculate the volume for the first condition as follows,

Substitute 0.0821 Latm/Kmol for R, 273 K for T, 2atm for P, 1 for n in the above equation,

$V=\frac{1 mol\times0.0821Latm\ Kmol\times273K}{2 atm} \\=11.20 L$

For the second condition,

$V=\frac{1mol\times0.0821 L atm/mol K\times546K}{1 atm} =44.8L$

For third condition,

$V=\frac{1mol\times0.0821 L atm/mol K\times409.5K}{1.50 atm} =22.4L$

Find more information about the ideal gas equation here,

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