Answer:
2 + 2i[tex]\sqrt{3}[/tex]
Step-by-step explanation:
note that [tex]\sqrt{-1}[/tex] = i
Given
[tex]\sqrt{4}[/tex] + [tex]\sqrt{-12}[/tex]
= 2 + [tex]\sqrt{4(3)(-1)}[/tex]
= 2 + ([tex]\sqrt{4}[/tex] × [tex]\sqrt{3}[/tex] × [tex]\sqrt{-1}[/tex] )
= 2 + 2i[tex]\sqrt{3}[/tex]
