AD is a diameter of circle ABCDE . Angle BAC=22° & angle ADC=60°. AE and ED are parallel lines. Find the values of w, x,y,and z
![AD is a diameter of circle ABCDE Angle BAC22 amp angle ADC60 AE and ED are parallel lines Find the values of w xyand z class=](https://us-static.z-dn.net/files/d33/5903238350b5130ae5065ed7300aead0.png)
Answer:
x = 22°
w = 30°
y = 30°
z = 52°
Step-by-step explanation:
From ΔACD,
AD is the diameter and ∠ACD is the angle subtended by the diameter.
Therefore, m∠ACD = 90°
By triangle sum theorem,
m∠DAC + m∠ACD + m∠CDA = 180°
w° + 90° + 60° = 180°
w = 180 - 150
w = 30°
AB║ED and AD is a transversal line.
Therefore, m∠BAD = m∠ADE
(w + 22)° = z°
30 + 22 = z
z = 52°
Since, ∠CEB and ∠BAC are the inscribed angles subtended by the same arc BC,
Therefore, m∠CEB = m∠BAC
x = 22°
Similarly, ∠CED and ∠DAC are the inscribed angles subtended by the same arc CD,
m∠CED = m∠DAC = 30°
y = 30°