Question

What are the solutions to the quadratic equation 4(x + 2)2 = 36
x= -11 and x = 7
x = -7 and x = 11
OOOO
x= -5 and x = 1
x= -1 and x = 5

Answer 1

Answer:

x = -5 and x = 1

Step-by-step explanation:

4( x2 + 4x + 4 ) = 36

4x2 + 16x + 16 = 36

4x2 + 16x - 20 = 0

x2 + 4x - 5 = 0

Answer 2

Answer:

C. x = -5, and x = 1

Step-by-step explanation:

You have the equation 4(x + 2)2 = 36

You then isolate 4 out of the equation using division on both sides

You are left with (x+2)2 = 9

Next, take square roots

$\sqrt({x} +2) ^{2}$ = $\sqrt{9}$

This leaves you with x + 2 ± 9

So, x = -2 + 3 = 1

or

x = -2 - 3 = -5