Question

A population of fish starts at 8000 and decreases by 6% per year. use an exponential function defined the population of fish in 10 years

Answer 1

Answer:

4308

Step-by-step explanation:

Answer 2

The population of fish at the end of 10 years will remain 4129 .

What is compound interest depreciation?

Depreciation is essentially a compound measure in the opposite direction, so decreasing the original value at a specific percentage at regular intervals. For depreciation you need to use the multiplier method for decreasing percentages and put this multiplier to the power of the number of time intervals in the question.

Formula of compound interest depreciation :

$A= P(1-\frac{r}{100} )^{n}$

Where,

A = final amount

P = initial principal

n = time in years

r = rate per annum

According to the question

A population of fish starts at (P)= 8000

decreases  per year (r) =  6%

n = 10

now , Applying Formula of compound interest depreciation :

$A= P(1-\frac{r}{100} )^{n}$

substituting the value

$A= 8000(1-\frac{6.4}{100} )^{10}$

$A= 8000(0.936} )^{10}$

A=8000 *  0.5161

A = 4,129.03 (approx.)

A = 4129 (round off to nearest whole no )

Hence,  the population of fish at the end of 10 years will remain 4129 .

To know more about compound interest depreciation here:

https://brainly.com/question/17186414

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