Question

A 4 kg block is pushed up an incline that makes a 30° angle with the horizontal, as shown in the figure. Once the block is pushed a distance of d = 5.0 m up the incline, the block remains at rest.
What is the approximate change in the gravitational potential energy of the block-Earth system when the block is held at rest compared to its original location at the bottom of the incline?
A) OJ
B) 100 J
C) 100/33 J
D) 200 J

Answer 1

Answer:

  B)  100 J

Explanation:

Assuming the distance given is measured along the incline, the vertical change in height is (5 m)(sin 30°) = 2.5 m. Then the change in potential energy is ...

  ∆PE = mg(∆h) = (4 kg)(10 m/s^2)(2.5 m) = 100 J

Answer 2

The force is defined as the product of the mass and the acceleration. The energy stored in an object which is converted into kinetic energy is called potential energy.

The formula for the potential energy is mgh.

The correct answer is B that is 100J.

As the surface is inclined the vertical change in height is$(5 m)(sin 30^o) = 2.5$m.

Therefore the potential energy after solving it is as follows:-

$PE = mg(h) \\= (4 kg)(10 m/s^2)(2.5 m)\\\\= 100 J$

For more information, refer to the link:-

https://brainly.com/question/2127750