consider the equation 10 2z/3=15.
solve the equation for z.
express the solution as a logarithm base-10
z=
approximate the value of z. round your answer to the nearest thousandth
z=

Respuesta :

leena

Hi there! :)

[tex]\large\boxed{z = 1.764}[/tex]

[tex]10x^{(2z/3)} = 15[/tex]

Rewrite as a logarithmic equation using this format:

[tex]a^{b} = c \\\\log_{a}c = b[/tex]

In this instance:

a = 10 (log is by default base 10)

b = 2z / 3

c = 15

Rewrite as the log equation:

[tex]log 15 = 2z/3[/tex]

Evaluate log (15):

[tex]1.176 = 2z / 3[/tex]

Multiply both sides by 3:

[tex]3.528 = 2z[/tex]

Divide both sides by 2:

[tex]z = 1.764[/tex]