Question

A solution was prepared by dissolving 35.0 g of NaCl in water to make a 0.5 L solution. What is the molarity of the solution? The molar mass of NaCl = 58.44 g/mol.

Answer 1

The molarity of the solution : 1.2 M

Further explanation

Molarity shows the number of moles of solute in every 1 liter of solute or mmol in each ml of solution

$\large{\boxed {\bold {M ~ = ~ \frac {n} {V}}}$

Where

M = Molarity

n = Number of moles of solute

V = Volume of solution

mass of NaCl=35 g

Volume of solution = 0.5 L

mol NaCl(MW=58.44 g/mol) :

$\tt mol=\dfrac{mass}{MW}\\\\mol=\dfrac{35}{58.44}\\\\mol=0.6$

The molarity :

$\tt M=\dfrac{0.6}{0.5}=1.2$