Answer:
These equations describe two lines that intersect at the point (-1, 8), one of them with a slope of 3, the other with a slope of -4.
Step-by-step explanation:
We can find the point where these two lines intersect by taking one of the equations, solving it for x, and substituting it into the other equation.
[tex]y = -4x + 4\\-4x = y - 4\\4x = 4 - y\\x = 1 - \frac{y}{4} \\\\y = 3x + 11\\y = 3(1 - \frac{y}{4}) + 11\\y = 3 - \frac{3y}{4} + 11\\y + \frac{3y}{4} = 3 + 11\\\frac{4y}{4} + \frac{3y}{4} = 14\\\frac{7y}{4} = 14\\y = \frac{4}{7} * 14\\y = 4 * \frac{14}{7}\\y = 4 * 2\\y = 8[/tex]
Now we can plug that into our first equation to find x
[tex]x = 1 - \frac{y}[4}\\x = 1 - \frac{8}[4}\\\\x = 1 - 2\\x = -1[/tex]
So these lines intersect at the point (-1, 8), one of them with a slope of 3, the other with a slope of -4
