Question

When a 0.292 kg mass on a string is swung at 8.45 m/s, it feels a centripetal acceleration of 78.9 m/s^2. What is the radius of the swing? (Unit = m)

Answer 1

Answer:

0.905

Explanation:

right answer

Answer 2

The radius of the swing is 0.905 m

Circular motion

From the question, we are to determine the radius of the swing

Using the centripetal acceleration formula

$a_{c}= \frac{v^{2} }{r}$

Where $a_{c}$ is the centripetal acceleration

v is the velocity

and r is the radius

From the given information,

v = 8.45 m/s

$a_{c} = 78.9 \ m/s^{2}$

Then,

$78.9 = \frac{8.45^{2} }{r}$

$r = \frac{8.45^{2} }{78.9}$

$r = \frac{71.4025}{78.9}$

r = 0.905 m

Hence, the radius of the swing is 0.905 m

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