Answer
3.65 liters is the volume of H₂ produced in the reaction
Explanation:
2 Al(s) + 6 HCI (aq) → 2AICI₃ (aq) + 3 H₂ (g)
I'll convert the mass of Al to moles.
2.93 g . 1mol/26.98 g = 0.108 moles
Ratio is 2:3. 2 moles of Al can produce 3 moles of H₂
Then, 0.108 moles of Al would produce (0.108 .3)/ 2 = 0.163 moles of H₂ Let's apply the Ideal Gases Law to find out the produced volume, at STP.
STP is 1 atm as pressure and 273K as T°
1 atm . V = 0.163 mol . 0.082L.atm/mol.K . 273K
V = (0.163 mol . 0.082L.atm/mol.K . 273K) / 1atm
V = 3.65 L
