Question

how do you put f(8)=-1,f(6)=0 into point slop form?​

Answer 1

Answer:

y + 1 = -1/2(x - 8)

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

1. Brackets
2. Parenthesis
3. Exponents
4. Multiplication
5. Division
6. Addition
7. Subtraction

• Left to Right

Algebra I

Slope Formula: $m=\frac{y_2-y_1}{x_2-x_1}$

Point-Slope Form: y - y₁ = m(x - x₁)  

• x₁ - x coordinate
• y₁ - y coordinate
• m - slope

Step-by-step explanation:

Step 1: Define

f(8) = -1 → Coordinate (8, -1)

f(6) = 0 → Coordinate (6, 0)

Step 2: Find slope m

1. Substitute [SF]:                    $m=\frac{0+1}{6-8}$
2. Add/Subtract:                      $m=\frac{1}{-2}$
3. Simplify:                               $m=\frac{-1}{2}$

Step 3: Write Function

Substitute into general form.

• Point 1: y + 1 = -1/2(x - 8)
• Point 2: y = -1/2(x - 6)