The missing sides are of the given triangle are of 26.69 units and 11.33 units.
Given that:
- One angle of a right angled triangle measures 67 degrees.
- Hypotenuse of that right angled triangle measures 29 units.
To find:
Missing sides of the triangle.
Calculations:
The sine trigonometric ratio gives us ratio of perpendicular to hypotenuse from perspective of the considered angle.
Referring to the figure attached below,
[tex]sin(\angle ACB)= \dfrac{AB}{AC}\\\\sin(67^\circ) = \dfrac{AB}{29}\\\\0.9205 \times 29 = AB\\\\AB = 26.69\\[/tex]
Similarly,
[tex]cos(\angle ACB)= \dfrac{BC}{AC}\\\\cos(67^\circ) = \dfrac{BC}{29}\\\\0.3907 \times 29 = BC\\\\BC = 11.33\\[/tex]
Thus, the missing sides are of the given triangle are of 26.69 units and 11.33 units.
Learn more about right angled triangles here:
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