Question

In \triangle BCD,△BCD, \overline{BC}\cong \overline{DB}
BC
≅
DB
and \text{m}\angle B = 147^{\circ}.m∠B=147
∘
. Find \text{m}\angle D.m∠D.

Answer 1

Answer:16.5

Step-by-step explanation: x+x+147=180

2x+147=180

2x=33

2x=33 divide by 2

x=16.5