Question

Answer quick please
For 0 < x < pi/2, which expression is equivalent to sin(x/2)tan(x/2)/1-cos(x) ?

Answer 1

Answer:

Its A dude

Step-by-step explanation:

Answer 2

The equivalent expression to$\frac{ sin(x/2)tan(x/2)}{1-cos(x)}$  is  $\frac{1}{\sqrt{2(cosx+1)} }$. option A is correct.

Equivalent expression to$\frac{ sin(x/2)tan(x/2)}{1-cos(x)}$  determine.

What is evaluation?

Evaluation is defined as finding a solutions to mathematical problems.

Here, we have $\frac{ sin(x/2)tan(x/2)}{1-cos(x)}$
$=\frac{sin(x/2)tan(x/2)}{1-cos(x)}\\ =\frac{sin(x/2)\frac{sin(x/2)}{cos(x/2)} }{2sin^2(x/2)} \\= \frac{sin(x/2)^2}{2cos(x/2)sin^2(x/2)}\\ =1/2cos(x/2)\\=\frac{1}{2\sqrt{(cos(x)+1})/2 } \\=\frac{1}{\sqrt{2(1+cos(x))} }$

Thus, the equivalent expression to$\frac{ sin(x/2)tan(x/2)}{1-cos(x)}$  is  $\frac{1}{\sqrt{2(cosx+1)} }$.

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