Question

During final exam weeks, many college students exercise to fuel their study sessions. Data from a recent survey are shown in the Venn diagram. Let M be the event that the student exercises in the morning and let A be the event that the student exercises in the afternoon.

A Venn diagram titled exercise habits. One circle is labeled M, 0.25, the other circle is labeled A, 014, the shared area is labeled 0.37, and the outside area is labeled 0.24.

What is the probability that a randomly chosen college student exercises in the morning or afternoon?

0.37
0.39
0.62
0.76

Answer 1

Answer:

WARNING! .39 AND .76 IS WRONG.

THE PEOPLE ABOVE ARE INCORRECT.

THE ANSWER IS EITHER .37 OR .62

I believe the correct answer is .62 --> .25 + .37 = .62 . This also makes sense.

(C)

ED2021

Answer 2

The probability that a randomly chosen college student exercises in the morning or afternoon are 0.37.

What is the probability?

Probability refers to a possibility that deals with the occurrence of random events. The probability of all the events occurring need to be 1.

P(E) = Number of favorable outcomes / total number of outcomes

From the given Venn diagram, we see that

Probability that the student exercises in the afternoon

P(A) = 0.14 + 0.37 = 0.51

Probability that the student exercises in the morning

P(M) = 0.25 + 0.37 = 0.61

Now, the probability that a randomly chosen college student exercises in the morning or afternoon

P(A ∩ M) = 0.37

Learn more about probability here;

https://brainly.com/question/11234923