Question

help..
The length of one side of a shoebox is 8 centimeters more than twice the width. The base of the shoebox has an area of 72 square centimeter.
Write an equation to represent this situation with w representing the width in centimeter

Answer 1

Answer:  $w^2+4w-36=0$

Step-by-step explanation:

Let w = width of the base of the shoebox.

As per given ,

Length = 8+2w centimeters

Area of base = 72 square centimeter

Area of rectangle =  Length x width

$\Rightarrow\ 72=w(2w+8)\\\\\Rightarrow\ 72= 2w^2+8w\\\\\Rightarrow\ 2w^2+8w-72=0\\\\\Rightarrow\ w^2+4w-36=0$

Required equation: $w^2+4w-36=0$