Question

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Daniel can spend no more than $40 at the fair. If admission into the fair is $10 and the rides cost $1.50 each, which inequality represents the greatest number of rides Daniel can go on?


A. 10r + 1.50 ≥ 40
B. 1.50r + 10 ≤ 40
C. 1.50r + 10 <40
D 10r+1.50<40

Explain your reasoning and solve the inequality :

Answer 1

Answer:

B

Step-by-step explanation:

The sum spent has to be either equal to or less than 40. So r many rides, each of them being 1.50, plus 10 dollars has to equal to less or equal to 40 dollars.

Answer 2

Answer:

The answer is B

The greatest number of rides Daniel can go on is 20.

Step-by-step explanation:

Total: The same or less than 40

Fair Admission: 10

ride: 1.50x

40 ≤ 10 + 1.5r

To solve:

40 ≤ 10 + 1.5r

40 - 10 ≤ 10 + 1.5r - 10

30 ≤ 1.5r

30 ÷ 1.5 ≤ 1.5r ÷ 1.5

20 ≤ r

The greatest number of rides Daniel can go on is 20.

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