Answer:
The magnitude is definitely sqrt 61
Step-by-step explanation:
I am unsure how to mathematically solve for the direction angle but my educated guess would be C magnitude of sqrt 61 and direction angle equal to approximately 40° because the vector is below halfway of the 90 degree angle.
The magnitude and the direction of vector a are √61 and 40°. Then the correct option is C.
The quantity which has magnitude, direction and follows the law of vector addition is called a vector.
From the graph, we can see that the coordinate points of the vector that is given as (0, 0) and (5, 6)
Let a be the vector.
Then the magnitude of the vector will be
[tex]\rm \overrightarrow{a} =\sqrt{(6-0)^2 + (5-0)^2 } \\\\\overrightarrow{a} =\sqrt{6^2 + 5^2 }\\\\\overrightarrow{a} =\sqrt{36 + 25}\\\\\overrightarrow{a} =\sqrt{61}[/tex]
The direction will be
[tex]\rm \theta = tan^{-1} \dfrac{5}{6}\\\\\theta = tan^{-1} 0.833\\\\\theta = 39.80 \approx 40^o[/tex]
The magnitude and the direction of vector a are √61 and 40°. Then the correct option is C.
More about the vector link is given below.
https://brainly.com/question/13188123
