m∠COX = m∠AOX + m∠
Answers:
COD
COE
COX
COA

Answer:
m∠COA
Step-by-step explanation:
m∠COX = 80°
Here,
m∠COX = 40° + m∠COA
m∠COX = 40° + 40° = 80°
Thus, m∠COX = m∠AOX + m∠COA
-TheUnknownScientist