Question

If 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L, the concentration of the resulting solution is A0.025 M B 0.050 M C 0.10 M D 0.50 M E 1.0 M M​

Answer 1

Answer: The concentration of the resulting solution is 0.025 M

Explanation:

According to the dilution law,

$M_1V_1=M_2V_2$

where,

$M_1$ = molarity of concentrated $NaOH$ solution = 1.0 M

$V_1$ = volume of concentrated $NaOH$ solution = 50 ml

$M_2$ = molarity of diluted $NaOH$ solution = ?

$V_2$ = volume of diluted $NaOH$ solution = 2.0 L = 2000 ml (1L=1000ml)

Putting in the values we get:

$1.0\times 50=M_2\times 2000$

$M_2=0.025M$

Therefore, concentration of the resulting solution is 0.025 M

Answer 2

The concentration of the resulting solution if 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L is 0.025M

HOW TO CALCULATE FINAL CONCENTRATION:

• The concentration of a solution can be calculated by using the following formula:

C1V1 = C2V2

Where;

1. C1 = initial concentration (M)
2. C2 = final concentration (M)
3. V1 = initial volume (L)
4. V2 = final volume (L)

According to this question;

1. C1 = 1.0M
2. V1 = 50mL
3. C2 = ?
4. V2 = 2000mL = 2L

• 1 × 50 = C2 × 2000

• 50 = 2000C2

• C2 = 50 ÷ 2000

• C2 = 0.025M

• Therefore, the concentration of the resulting solution if 50. mL of 1.0 M NaOH is diluted with distilled water to a volume of 2.0 L is 0.025M.

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