Question

A student wearing a frictionless roller skates on a horizontal is pushed by a friend with a constant force of 55N. How far must the student be pushed, starting from rest, so that her final kinetic energy is 362 J

Answer 1

Answer:

6.58m

Explanation:

The kinetic energy = Workdone on the roller

Workdone = Force * distance

Given

KE = Workdone = 362J

Force = 55N

Required

Distance

Substitute into the formula;

Workdone = Force * distance

362 = 55d

d = 362/55

d = 6.58m

Hence the student must push at a distance of 6.58m