Question

A sample of gas is put into a container with a movable piston that will allow pressure to be maintained. If the sample of gas was initially at 6.50 degrees Celsius and occupied a volume of 11.7 L, what temperature would the sample be if the piston changed the volume to 89.1 L?

Answer 1

Answer:

2129.72 K

Explanation:

In this experiment, both the amount of gas and the pressure remain constant.

Those are the conditions for Charles' law:

• V₁T₂=V₂T₁

For this problem:

• V₁ = 11.7 L

• V₂ = 89.1 L

• T₁ = 6.50 °C

• T₂ = ?

We need to calculate T₂, but first we'll convert 6.50 °C to K:

• 6.50 + 273.16 = 279.66 K

Now we input the data on the equation:

• 11.7 L * T₂ =89.1 L * 279.66 K

And solve for T₂:

• T₂ = 2129.72 K