Answer:
377mL is the volume of the solution
Explanation:
A 0.140M solution of CuNO₃ contains 0.140 moles of CuNO₃ per liter of solution. Thus, we need to convert first the mass of CuNO₃ to moles using its molar mass and, with the moles available, we can find the volume of the solution, thus:
Moles CuNO₃ -Molar mass: 125.55g/mol:
6.63g * (1mol / 125.55g) = 0.0528 moles of CuNO₃.
Volume of solution:
0.0528 moles of CuNO₃ * (1L / 0.140 moles CuNO₃) = 0.377L
0.377L * (1000mL / 1L) =