Question

which equation represents the line that passes through points (5, 4) and (-5, 0)

Answer 1

Find slope: (y2-y1)/(x2-x1)
(0-4)/(-5-5) = -4/-10 = 2/5
Y = 2/5x + b
Plug in one point
4 = 2/5(5) + b, b = 2
Solution: y = 2/5x + 2

Answer 2

The equation should be $y = 2\div 5x + 2$

Given that,

• The points are (5, 4) and (-5, 0)

Based on the above information, the calculation is as follows:

here we need to find the slope.

$= (y_2-y_1)\div (x_2-x_1)\\\\= (0-4)\div (-5-5) \\\\= -4\div -10 \\\\= 2\div 5\\\\Y = 2\div 5x + b$

Now  

Put in one point

$4 = 2\div 5(5) + b, b = 2$

So,

$y = 2\div 5x + 2$

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