Respuesta :
Answer:
C₃H₅N₃O₉
Explanation:
Molar mass of nitroglycerin (Ratio of mass and moles of the compound) is:
1.00g / 0.0041mol = 226.8g/mol
We can write the equations:
0.6H = C (1)
-60% as many carbon atoms as hydrogen atoms-
3N = O (2)
C = N
Using as basis the atoms of Carbon:
Carbon = 1
Nitrogen = 1
Oxygen = 3
Hydrogen = 1/0.6 = 1.67
A molecular formula has just whole numbers. This ratio of atoms times 3:
Carbon = 3
Nitrogen = 3
Oxygen = 9
Hydrogen = 5
C₃H₅N₃O₉. Molar mass of this formula is:
C = 12.01g/mol*3 = 36.03g/mol
H = 1.01g/mol*5 = 5.05g/mol
N = 14g/mol*3 = 42g/mol
O = 16g/mol*9 = 144g/mol
Molar mass:
36.03g/mol + 5.05g/mol + 42g/mol + 144g/mol = 227g/mol ≈ 226.8g/mol
That means molecular formula of nitroglycerin is:
C₃H₅N₃O₉
The molecular formula of nitroglycerin is C₃H₅O₉N₃
Mass of nitroglycerin = 1.00 g
A number of moles of nitroglycerin = 0.0041 mol
It is required to calculate the molecular formula of nitroglycerin.
What is the empirical formula?
An empirical formula tells us the relative ratios of different atoms in a compound.
The molecular formula of nitroglycerin can be estimated with the help of empirical formula.
The molar mass of nitroglycerin (Ratio of mass and moles of the compound) is:
1.00g / 0.0041mol = 226.8 g/mol
We can write the equations:
0.6H = C (1)
-60% as many carbon atoms as hydrogen atoms-
3N = O (2)
C = N
Using as basis the atoms of Carbon:
Carbon = 1
Nitrogen = 1
Oxygen = 3
Hydrogen = 1/0.6 = 1.67
A molecular formula has just whole numbers. This ratio of atoms times 3:
Carbon = 3
Nitrogen = 3
Oxygen = 9
Hydrogen = 5
C₃H₅N₃O₉.
Molar mass of this formula is:
C = 12.01g/mol*3 = 36.03g/mol
H = 1.01g/mol*5 = 5.05g/mol
N = 14g/mol*3 = 42g/mol
O = 16g/mol*9 = 144g/mol
Molar mass:
36.03g/mol + 5.05g/mol + 42g/mol + 144g/mol = 227g/mol ≈ 226.8g/mol
That means molecular formula of nitroglycerin is:
C₃H₅N₃O₉
To learn more about empirical formula, click here:
https://brainly.com/question/11588623
